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happinessisawarmgun 28 ( +1 | -1 )
how many queens..? Theoretically , what is the maximum number of queens that can be on the board at any one time taking into consideration pawns will have to capture other pawns in order to pass. If anyone knows please share as I think this will help my learning !!! Tnx
honololou 46 ( +1 | -1 )
theoretically… I think it would be possible to have 18 queens since pawns
would not need to capture other pawns but could capture
pieces to pass. Of course there are only six pieces a side
(minus queen and king) to capture but by doubling and/or
tripling pawns I believe it would be possible (in theory) to
queen all your pawns and keep the original queens as well.
Don't see how this knowledge could help your game,
lespaul 29 ( +1 | -1 )
Would it be possible... To have 18 Queens on the board at one time, and have a king NOT checkmated?
The king couldn't exactly be surrounded by pieces, as the pawns would need to take many of them to bypass the other pawns.

I can't conceive any situation where there could be 18 Queens and 2 free kings.
zoobrenok 60 ( +1 | -1 )
yes, it is possible.

In fact someone here on GK did it last year.

I don't remember board number and I don't think forum thread is still here...

if you look into the chess books you probably can find it..

by the way -- me and episode played a game here on GK where we promoted all pawns into the knights :-).

anyone would like to play a game where all pawns are promoted to white only bishops? --> this would be a good, very good challenge..
More: Chess
atrifix 5 ( +1 | -1 )
The King could be surrounded by the queens, of course.
calmrolfe 31 ( +1 | -1 )
Don't be silly !! How on earth can you possibly have 18 Queens on a chessboard legally !!

Think about it, each side has eight pieces, one of which is a King and cannot be taken, another is a Queen, if you take that you are one Queen less !!

There is something fundamentally wrong with your reasoning......

Kind regards,

zdrak 22 ( +1 | -1 )
There are a grand total of 12 pieces that can be captured: 4x bishop, 4x knight, 4x rook.

In order for 8 pairs of pawns to bypass each other, only 8 captures need to be made: 4 by white, 4 by black.

So I don't see why it's impossible.
zdrak 34 ( +1 | -1 )
Take this "game" for example:

1. a4 a5
2. b4 c5
3. b5 d5
4. c4 d4
5. e4 e5
6. d3 b6
7. f4 f6
8. f5 g5
9. g4 h5
10. h3 h4
11. Nc3 dxc3
12. d4 Nc6
13. bxc6 b5
14. d5 b4
15. Ne2 Ba6
16. Ng3 hxg3
17. h4 Bb5
18. axb5 a4
19. h5 Ne7
20. Rh4 gxh4
21. g5 Ng6
22. fxg6 f5
23. h6 f4
24. Be3 Rh7
25. Bd4 Rf7
26. h7 Rf5
27. exf5 cxd4
28. f6

See, all pawns have passed each other, and each side still has his original queen. Now the process of promoting all the pawns to queens (while using the newborn queens to shelter the kings) is merely technical.
calmrolfe 23 ( +1 | -1 )
I take it all back !! You are absolutely correct, I've just replayed your moves and you are indeed right. 18 Queens it is then !!


killmaster 30 ( +1 | -1 )
theoretically... zdrak has shown it is posible to have 18 queens on board.Practically, I have only seen five queens (of mine) on board in a blitz tourney, when my opponent saw me going for the sixth one he resigned which was rather too late,two chicks had already collected my autograph...just kidding!
mormel12 25 ( +1 | -1 )
yes, i've seen that game with the 18 queens here, but i also don't know the boardnumber anymore.
but this one is nice as well board #530820 (sorry john:))
lordoftherings 0 ( +1 | -1 )
18.. 18..